解:原式毁岩=(2a+2/a-1)*(1/a-1)+a^2-1/(a-1)^2 =2/纤局御a-1+(a-1)(a+1)/(a-1)^2 =2/a-1+(a+1/a-1) =a+3/a-1=(3+4根号3)/腊纤3
3份之2