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已知(x+y)(x+y-10)+25=0,且x-y=2,求x,y的值?
被浏览: 0次 2023年04月27日 08:27
热门回答(6个)
游客1

(x+y)(x+y-10)+25=0,
(x+y)²帆脊谨-10(x+y)+25=0
(x+y-5)²态基=0
x+y-5=0
x+y=5
∵野锋x-y=2
∴x=3.5, y=1.5

游客2

x+y)(x+y-10)+25=0,且
x-y=2,
x=2+y
代芹弊入(x+y)(x+y-10)+25=0,得
(2+2y)嫌槐族(明猜2+2y-10)+25=0
2+2y=5
y=3/2
x=7/3

游客3

(x+y)*(x+y-10)+25=0, (x+y)²-10(x+y)+25=0 (x+y-5)²=0
x+y=5 x-y=2
联立嫌铅得念纤x=7/仔者仿2, y=3/2

游客4

我蔽庆来帮宏悔握您前卖吧!
(x+y)(x+y-10)+25=0,
解: (x+y)²-10(x+y)+25=0
(x+y-5)²=0
x+y-5=0
x+y=5
∵x-y=2
∴x=3.5, y=1.5

游客5

x=y+2,代入(昌腔x+y)(x+y-10)+25=0,得:(2y+2)(2y-8)斗迅档+25=0,解得:空乱y=3/2,x=3/2+2=7/2

游客6

qq